2x^2=210

Solution for 2x^2=210 equation:

2x^2=210

We move all terms to the left:

2x^2-(210)=0

a = 2; b = 0; c = -210;
Δ = b2-4ac
Δ = 02-4·2·(-210)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*2}=\frac{0-4\sqrt{105}}{4}
=-\frac{4\sqrt{105}}{4}
=-\sqrt{105}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*2}=\frac{0+4\sqrt{105}}{4}
=\frac{4\sqrt{105}}{4}
=\sqrt{105}
$